Codeforces Calculating Function 486A



A solution in c++

#include<bits/stdc++.h>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>

using namespace std;

int main()
{
   long long int a, b, ck1=0,i,j,sum=0,sum1=0;
   scanf("%lld",&a);
   if(a%2==0){
     ck1 = a/2;
    printf("%lld\n", ck1);
   }
   else{
    ck1 = (((a/2)+1)*(-1));
     printf("%lld\n", ck1);
   }
}

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